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author | upstream source tree <ports@midipix.org> | 2015-03-15 20:14:05 -0400 |
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committer | upstream source tree <ports@midipix.org> | 2015-03-15 20:14:05 -0400 |
commit | 554fd8c5195424bdbcabf5de30fdc183aba391bd (patch) | |
tree | 976dc5ab7fddf506dadce60ae936f43f58787092 /gcc/testsuite/gcc.c-torture/execute/pr15262-1.c | |
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Diffstat (limited to 'gcc/testsuite/gcc.c-torture/execute/pr15262-1.c')
-rw-r--r-- | gcc/testsuite/gcc.c-torture/execute/pr15262-1.c | 47 |
1 files changed, 47 insertions, 0 deletions
diff --git a/gcc/testsuite/gcc.c-torture/execute/pr15262-1.c b/gcc/testsuite/gcc.c-torture/execute/pr15262-1.c new file mode 100644 index 000000000..f6a6fe40b --- /dev/null +++ b/gcc/testsuite/gcc.c-torture/execute/pr15262-1.c @@ -0,0 +1,47 @@ +/* PR 15262. + The alias analyzer only considers relations between pointers and + symbols. If two pointers P and Q point to the same symbol S, then + their respective memory tags will either be the same or they will + have S in their alias set. + + However, if there are no common symbols between P and Q, TBAA will + currently miss their alias relationship altogether. */ +struct A +{ + int t; + int i; +}; + +int foo () { return 3; } + +main () +{ + struct A loc, *locp; + float f, g, *p; + int T355, *T356; + + /* Avoid the partial hack in TBAA that would consider memory tags if + the program had no addressable symbols. */ + f = 3; + g = 2; + p = foo () ? &g : &f; + if (*p > 0.0) + g = 1; + + /* Store into *locp and cache its current value. */ + locp = malloc (sizeof (*locp)); + locp->i = 10; + T355 = locp->i; + + /* Take the address of one of locp's fields and write to it. */ + T356 = &locp->i; + *T356 = 1; + + /* Read the recently stored value. If TBAA fails, this will appear + as a redundant load that will be replaced with '10'. */ + T355 = locp->i; + if (T355 != 1) + abort (); + + return 0; +} |