From 554fd8c5195424bdbcabf5de30fdc183aba391bd Mon Sep 17 00:00:00 2001
From: upstream source tree <ports@midipix.org>
Date: Sun, 15 Mar 2015 20:14:05 -0400
Subject: obtained gcc-4.6.4.tar.bz2 from upstream website; verified
 gcc-4.6.4.tar.bz2.sig; imported gcc-4.6.4 source tree from verified upstream
 tarball.

downloading a git-generated archive based on the 'upstream' tag
should provide you with a source tree that is binary identical
to the one extracted from the above tarball.

if you have obtained the source via the command 'git clone',
however, do note that line-endings of files in your working
directory might differ from line-endings of the respective
files in the upstream repository.
---
 gcc/testsuite/gcc.dg/tree-ssa/pr23234.c | 58 +++++++++++++++++++++++++++++++++
 1 file changed, 58 insertions(+)
 create mode 100644 gcc/testsuite/gcc.dg/tree-ssa/pr23234.c

(limited to 'gcc/testsuite/gcc.dg/tree-ssa/pr23234.c')

diff --git a/gcc/testsuite/gcc.dg/tree-ssa/pr23234.c b/gcc/testsuite/gcc.dg/tree-ssa/pr23234.c
new file mode 100644
index 000000000..3a3869815
--- /dev/null
+++ b/gcc/testsuite/gcc.dg/tree-ssa/pr23234.c
@@ -0,0 +1,58 @@
+/* The problem in this PR was mostly finding a suitable place to insert
+   the reciprocals of the function arguments.  This test case tries to
+   test three possible ways of how this may go wrong.  */
+/* { dg-options "-O2 -ffast-math" } */
+/* { dg-do compile } */
+
+/* The original test case.  */
+double
+f1 (double a, double b, double c)
+{
+  double y0;
+  double y1;
+
+  if (a == 0.0)
+    {
+      y0 = -c / b;
+      return y0;
+    }
+  y0 = c / b;
+  y1 = a / b;
+  return y0 * y1;
+}
+
+/* Labels may end up in the middle of a block.  Also bad.  */
+double
+f2 (double a, double b, double c)
+{
+  double y0;
+  double y1;
+
+a_label:
+another_label:
+  if (a == 0.0)
+    {
+      y0 = -c / b;
+      return y0;
+    }
+  y0 = c / b;
+  y1 = a / b;
+  return y0 * y1;
+}
+
+/* Uses must still be dominated by their defs.  */
+double
+f3 (double a, double b, double c)
+{
+  double y0;
+  double y1;
+
+  y0 = -c / b;
+  if (a == 0.0)
+    {
+      return y0;
+    }
+  y0 = c / b;
+  y1 = a / b;
+  return y0 * y1;
+}
-- 
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