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// { dg-do run }
// Testcase for implicit 'typename' and resolution of 'typename's in the
// current scope.
class base1 {
public:
int bar() const
{ return 1; }
};
class base2 {
public:
int bar() const
{ return 0; }
};
template<class X>
struct base_trait {
typedef base1 base;
};
template<>
struct base_trait<float> {
typedef base2 base;
};
template<class T>
class weird : public base_trait<T>::base {
public:
typedef typename base_trait<T>::base base;
base f ();
int base::* g ();
int zowee() const
{ return this->bar(); }
};
template <class T>
typename weird<T>::base weird<T>::f ()
{
return base();
}
// The standard does not allow this case; the `typename' keyword may
// not appear in a ptr-operator.
#if 0
template <class T>
int typename weird<T>::base::* weird<T>::g ()
{ return 0; }
#endif
int main()
{
weird<float> z;
return z.zowee() || z.f().bar();
}
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